2.14 Decimal Word Problems

Introduction

Unit 1

Unit 2

Unit 3

Unit 4

Unit 5

Unit 6

Math Basics  >  Unit 2 Fractions and Decimals  >  Lesson 2.14 Decimal Word Problems

Video Lesson

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Practice Activity

Solve the word problem then click on your answer to see if it's correct.

+ Video Transcript

Now we're going to look at an example of a word problem that has decimals. A rectangular frame has an area of 42.84 square inches and a width of 5.1 inches. Find the length of the frame. So let's set up a little picture to help us see what this looks like. So there's a rectangular frame. We know that the width is 5.1 but we don't know what the length is. So we can just put a little question mark there. We do know however, what the area is. They tell us that the area is 42.84. So that's going to come in handy to help us figure out what the length is. We know that to calculate the area we multiply the length times width. But we're not trying to find the area, we're trying to find the length with this problem. So we can rearrange this formula to solve for the length. The length is going to be equal to the area divided by the width. Now we know what the area is, we know what the width is, we can plug those numbers in. So to find the length we're going to divide the area which is 42.84 by the width which is 5.1. So now we know what calculation we need to do. Let's go ahead and set it up. We can set up with long division. Remember when we're dividing with decimals we want to set it up as long division. And then we look to see if our divisor has a decimal in it or not. And it does. We have 5.1. We want our divisor to be a whole number. So we need to move the decimal point over to the right however many places we need to so that we have a whole number. With this we can just move it over one place to the right so that it's after the last number after the one. And we're going to make this 51 so it's a whole number. We have to do the same thing to the dividend on the inside. So we're going to move that decimal point over so that it's after the eight. And all we're really doing here is multiplying both of these numbers by ten, which the end result is the decimal point just moving over to the right. So now we can rewrite this showing that our devisor’s a whole number this time. So we have 428.4 divided by 51. Since our dividends does a decimal point in it, we're going to drag that decimal point up so that we know where it will be in the quotient. And now we can focus on dividing the numbers. So 51 goes into 428 eight times, we multiply 51 times eight, get 408. Subtract, we have 20 left. Bring down the four. And 51 goes into 204 four times you multiply and we do get exactly 204. So there's no remainder left over. So we can now see that the length of this frame is 8.4 inches.

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